A person travels from X to Y at a speed of 40 kmph and returns by increasing his speed 50%. What is his average speed for both the trips?
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Let the distance from X to Y = x km
Speed towards from X to Y = 40 kmph
Time taken = (x/40)
Returing spreed from Y to X = 40+(50% of 40) = 40+20 = 60 kmph
Time taken in journey = (x/60)
Average speed for whole journey = Total Distance/Total time
Total Distance = 2x
Total time = (x/40+x/60)
Average speed = 2x/(x/40+x/60) = 4800/100 = 48 kmph