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Asked: 2023-03-18T04:16:08+05:30 In:

Number 136 is added to 5B7 and the sum obtained is 7A3, where A and B are integers. It is given that 7A3 is exactly divisible by 3. The only possible value of B is:

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Number 136 is added to 5B7 and the sum obtained is 7A3, where A and B are integers. It is given that 7A3 is exactly divisible by 3. The only possible value of B is:

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14.29%(a) 2 ( 1 voter )
0%(b) 5 ( 0 voters )
28.57%(c) 7 ( 2 voters )
57.14%(d) 8 ( 4 voters )
Based On 7 Votes

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1 Answer

  1. Anonymous
    This answer was edited.

    Ans (d) 8
    ‘7A3’ is divisible by 3 only when the sum of its digits is divisible by 3.
    Rule of Divisible of 3
    7 + A + 3 = 10 + A
    Now, (10 + A) would be divisible by 3, for A = 2, 5, 8
    As per the question,
    136 + 5B7 = 7A3
    5B7 = 7A3 – 136

    For A = 2,
    5B7 = 723 – 136 = 587
    B = 8
    Hence, B = 8.

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